# How do you write a quadratic function in vertex form whose graph has the vertex (2,-4) and point (0,0)?

##### 1 Answer

Aug 14, 2017

#### Explanation:

#"the equation of a parabola in "color(blue)"vertex form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#

where ( h , k ) are the coordinates of the vertex and a is a constant.

#"here vertex "=(2,-4)=(h,k)#

#rArry=a(x-2)^2-4#

#"to find a substitute "(0,0)" into the equation"#

#0=4a-4rArra=1#

#rArry=(x-2)^2-4larrcolor(red)" in vertex form"#

graph{(x-2)^2-4 [-10, 10, -5, 5]}