# How do you find the vertex of y=4(x-3)^2-1?

Dec 10, 2015

This parabola is already in vertex form ...

#### Explanation:

Vertex form is:

$y = a {\left(x - h\right)}^{2} + k$ with vertex $\left(h , k\right)$

For this problem, vertex $= \left(3 , - 1\right)$

hope that helped