# How do you find the vertex of #y = x^2 - 4x - 12#?

##### 2 Answers

It is in

#### Explanation:

The vertex is the minimum or the maximum of a parabola. Then it is enough to search the zero of the derivative. We want to solve

that is

and

To find the

The vertex is then in the point

graph{x^2-4x-12 [-9.255, 10.735, -17.9, -7.89]}

Vertex at

#### Explanation:

The general vertex form for a parabola is

with vertex at

Converting the given equation

(extracting the

(into vertex form)

with vertex at

For verification purposes, here is the graph of the given equation:

graph{x^2-4x-12 [-13.07, 18.96, -16.62, -0.59]}