# How do you find the vertex of #y = x^2-8x+7#?

##### 1 Answer

Jan 25, 2016

#### Explanation:

Factor

#y = x^2 -8x +7# .

That's

#y = (x-4)^2 - 9# .

Then, transpose

#y+9 = (x-4)^2# .

Remember:

Vertex will be