# How do you find the vertices and foci of #y^2/49-x^2=1#?

##### 1 Answer

Jan 26, 2017

Given the general Cartesian form:

The vertices are

The foci are

#### Explanation:

Write the given equation,

Insert -0 with the square both numerators:

Write the 49 as

Matching the variables in equation [1] with the values in equation [2],

Compute

Now, it is a simple matter to write the vertices and foci.

Vertices:

Foci: