# How do you find the vertices, asymptote, foci and graph #x^2/144-y^2/121=1#?

##### 1 Answer

Jul 7, 2018

Please see the explanation below

#### Explanation:

This is the equation of a hyperbola

Here, we have

The center is

The vertices are

and

The equations of the asymptotes are

That is

Calculate

The foci are

And the graph is

graph{(x^2/144-y^2/121-1)(y-11/12x)(y+11/12x)=0 [-65.8, 65.84, -32.95, 32.9]}