# How do you find the vertices, asymptote, foci and graph #x^2/36-y^2=1#?

##### 1 Answer

May 17, 2017

The General form for a hyperbola of this type is:

Vertices:

Foci:

Asymptotes:

#### Explanation:

Here is a reference for Hyperbola equations provided in the answer section.

Let's convert the given equation,

By inspection of equation [2] we observe that

Vertices:

Foci:

Asymptotes:

Here is a graph:

graph{x^2/36-y^2=1 [-10, 10, -5, 5]}