How do you find the x and y intercepts for #3x+2y=1#?

2 Answers

Answer:

x-intecept = #1/3# , y-intercept = #1/2#

Explanation:

If you write the equation as follows :

#2y = -3x + 1#

#rArr# #y = (-3x)/2 + 1/2#

And compare it to the slope intercept form of linear equations,
You find that y-intercept is #1/2#.

And If you do this :

#3x = -2y + 1#

#rArr# #x = (-2y)/3 + 1/3#

Here, the x - intercept is #1/3#.

See in the graph:

graph{3x + 2y = 1 [-1.199, 1.202, -0.599, 0.601]}

May 9, 2017

Answer:

Intercept on #x#-axis is #1/3# and on #y#-axis is #1/2#

Explanation:

There are two ways of doing this.

One - If a line has intercepts #a# on #x#-axis and #b# on #y#-axis, then its equation is #x/a+y/b=1#

Now we can write #3x+2y=1#

as #x/(1/3)+y/(1/2)=1#

Hence, intercept on #x#-axis is #1/3# and on #y#-axis is #1/2#

Two - We can find #x# intercept by putting #y=0# and #y# intercept by putting #x=0# (this method is applicable even on non-linear equations.

Putting #y=0# we get #3x=1# or #x=1/3# and putting #x=0#, we get #2y=1# or #y=1/2#.

Hence, intercept on #x#-axis is #1/3# and on #y#-axis is #1/2#

graph{3x+2y=1 [-2.532, 2.47, -0.96, 1.54]}