# How do you find the x and y intercepts for #y = x + 5 #?

##### 2 Answers

#### Explanation:

#"to find the intercepts, that is where the graph crosses the"#

#"x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArry=0+5=5larrcolor(red)"y-intercept"#

#y=0rArrx+5=0rArrx=-5larrcolor(red)"x-intercept"#

graph{(y-x-5)((x-0)^2+(y-5)^2-0.04)((x+5)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

**x-intercept **

**y-intercept **

#### Explanation:

**Given:**

**Step 1**

**Slope-Intercept Form** of the linear equation of a line, where **Slope** and **y-intercept**.

The **linear equation** **Slope-Intercept Form**.

Hence,

**Slope (m) = **

**y-intercept = **

To plot this point on the graph, we write it as

**Step 2**

To find the **x-intercept**, set

Hence, the given equation

Subtract

To plot this point on the graph, we write it as

Hence,

**x-intercept **

**y-intercept **

Please refer to the graph below to verify the solutions visually:

graph{y=x+5 [-20, 20, -10, 10]}

Hope it helps.