How do you find the x and y intercepts of #6y=3x+6#?

1 Answer
Mar 6, 2018

Answer:

#x#-intercept is #-2# and #y#-intercept is #1#

Explanation:

To find #x#-intercept of any line (actually, I should say any curve) just put #y=0#

and to #x#-intercept of any line (again any curve) just put #x=0#.

Hence #x#-intercept of #6y=3x+6# is given by #6*0=3x+6# or #3x=-6# i.e. #x=-2#

and #y#-intercept of #6y=3x+6# is given by #6y=3*0+6# or #6y=6# i.e. #y=1#.

graph{6y=3x+6 [-2.958, 2.042, -1, 1.5]}