How do you find the y intercept, axis of symmetry and the vertex to graph the function #f(x)=3x^2+1#?

1 Answer
Jun 15, 2018

#y = 1#
#x = 0#
#(0,1)#

Explanation:

The y-intercept is the point where #x = 0#. 'y' is the same as the #f(x)# of the expression.
#y = 3x^2 + 1# ; #y = 3(0)^2 + 1# ; #y = 1#

The vertex is the min/max of the function, which is the same as the y-intercept in this case: #(0,1)#
It is the point were the first derivative of the function is zero.
#0 = 6x#; #x = 0#
The axis of symmetry is the line in the middle of the curve, #x = 0#