How do you find the zeros by rewriting the function y=2x^2-26x+24 in intercept form?
1 Answer
Jun 28, 2018
Explanation:
"the intercept form is "y=a(x-p)(x-q)
"where p and q are the x-intercepts"
"to obtain this form factor the quadratic"
"to obtain the zeros set y = 0"
2x^2-26x+24=0
"divide all terms by 2"
x^2-13x+12=0
"the factors of "+12" which sum to "-13"
"are "-1" and "-12
(x-1)(x-12)=0larrcolor(blue)"in intercept form"
"equate each factor to zero and solve for "x
x-1=0rArrx=1
x-12=0rArrx=12