How do you find the zeros by rewriting the function y=2x^2-26x+24 in intercept form?

1 Answer
Jun 28, 2018

x=1" or "x=12

Explanation:

"the intercept form is "y=a(x-p)(x-q)

"where p and q are the x-intercepts"

"to obtain this form factor the quadratic"

"to obtain the zeros set y = 0"

2x^2-26x+24=0

"divide all terms by 2"

x^2-13x+12=0

"the factors of "+12" which sum to "-13"

"are "-1" and "-12

(x-1)(x-12)=0larrcolor(blue)"in intercept form"

"equate each factor to zero and solve for "x

x-1=0rArrx=1

x-12=0rArrx=12