How do you find the zeros by rewriting the function #y=2x^2-26x+24# in intercept form?

1 Answer
Jun 28, 2018

Answer:

#x=1" or "x=12#

Explanation:

#"the intercept form is "y=a(x-p)(x-q)#

#"where p and q are the x-intercepts"#

#"to obtain this form factor the quadratic"#

#"to obtain the zeros set y = 0"#

#2x^2-26x+24=0#

#"divide all terms by 2"#

#x^2-13x+12=0#

#"the factors of "+12" which sum to "-13"#

#"are "-1" and "-12#

#(x-1)(x-12)=0larrcolor(blue)"in intercept form"#

#"equate each factor to zero and solve for "x#

#x-1=0rArrx=1#

#x-12=0rArrx=12#