Question

How do you find the zeros by rewriting the function `y=x^2+16x+64` in intercept form?

Answer 1

`y=(x+8)^2`

Explanation:

We write the function as `y=f(x)` and factorize `f(x)` to find intercepts on `x`-axis. If `f(x)=a(x-alpha)(x-beta)`, the zeros of `f(x)` are `alpha` and `beta` and intercepts are `alpha` and `beta` and `y=a(x-alpha)(x-beta)` is the equation in intercept form.

Here we have `y=x^2+16x+64=(x+8)^2`

Hence, we have just one intercept `x=-8`

graph{(x+8)^2 [-16.42, 3.58, -4.08, 5.92]}