How do you find the zeros by rewriting the function #y=x^2+16x+64# in intercept form?

1 Answer
Aug 27, 2017

Answer:

#y=(x+8)^2#

Explanation:

We write the function as #y=f(x)# and factorize #f(x)# to find intercepts on #x#-axis. If #f(x)=a(x-alpha)(x-beta)#, the zeros of #f(x)# are #alpha# and #beta# and intercepts are #alpha# and #beta# and #y=a(x-alpha)(x-beta)# is the equation in intercept form.

Here we have #y=x^2+16x+64=(x+8)^2#

Hence, we have just one intercept #x=-8#

graph{(x+8)^2 [-16.42, 3.58, -4.08, 5.92]}