How do you find the zeros by rewriting the function #y=x^2+4x+3# in intercept form?

1 Answer
Aug 23, 2017

Answer:

#x=-3,x=-1#

Explanation:

#"factorise the quadratic "x^2+4x+3#

#"the product of the factors of +3 which sum to + 4"#
#"are + 1 and + 3"#

#rArry=(x+1)(x+3)larrcolor(red)" in intercept form"#

#"to find the zeros equate y to zero"#

#rArr(x+1)(x+3)=0#

#"equate each factor to zero and solve for x"#

#x+1=0rArrx=-1#

#x+3=0rArrx=-3#
graph{x^2+4x+3 [-10, 10, -5, 5]}