# How do you find the zeros of #y=12x^2+8x-15#?

##### 1 Answer

Apr 2, 2017

#### Answer:

Two real roots:

#### Explanation:

Solve y = 12x^2 + 8x - 15 = 0 by the new Transforming Method (Socratic Search)

Transformed equation y' = x^2 + 8x - 180 = 0

Compose factor pairs of (-180) --> ... (10, -18). This sum is -8 = -b.

The 2 real roots of y' are: 10 and - 18.

The 2 real roots of y are: