# How do you find the zeros of y=12x^2+8x-15?

Apr 2, 2017

Two real roots: $\frac{5}{6} \mathmr{and} - \frac{3}{2}$

#### Explanation:

Solve y = 12x^2 + 8x - 15 = 0 by the new Transforming Method (Socratic Search)
Transformed equation y' = x^2 + 8x - 180 = 0
Compose factor pairs of (-180) --> ... (10, -18). This sum is -8 = -b.
The 2 real roots of y' are: 10 and - 18.
The 2 real roots of y are:
$x 1 = \frac{10}{a} = \frac{10}{12} = \frac{5}{6}$ and
$x 2 = - \frac{18}{a} = - \frac{18}{12} = - \frac{3}{2}$