# How do you find three consecutive even integers if the sum of the first two minus the third is 16?

Mar 13, 2016

Express the condition in symbolic form and solve to find the three integers are:

$18 , 20 , 22$

#### Explanation:

Let the smallest of the three consecutive integers be $n$. Then the other two are $n + 2$ and $n + 4$.

The condition in the question can be expressed:

$n + \left(n + 2\right) - \left(n + 4\right) = 16$

That simplifies to :

$n - 2 = 16$

Hence $n = 16 + 2 = 18$

So the three integers are $18$, $20$, $22$.