# How do you find three consecutive odd integers such that the sum of the largest and twice the smallest is 25?

May 30, 2018

$\implies 7 , 9 , 11$

#### Explanation:

Let the smallest consecutive odd number be $n$. Then the next two consecutive odd integers are $n + 2$ and $n + 4$.

"Sum of the largest and twice the smallest is $25$"

$\left(n + 4\right) + 2 \left(n\right) = 25$

$n + 4 + 2 n = 25$

$3 n + 4 = 25$

$3 n = 21$

$\implies n = 7$

So the three numbers ($n$, $n + 2$, $n + 4$) are: $7 , 9 , 11$