# How do you find three consecutive odd integers such that twice the sum of the smaller two integers is 25 more than 3 times the largest?

nos are $33 , 35 , 37$
$2 \cdot \left(x + x + 2\right) = 3 \cdot \left(x + 4\right) + 25$
$4 \cdot x + 4 = 3 \cdot x + 12 + 25$
$x = 33$
nos are $33 , 35 , 37$