# How do you find x-intercepts, coordinates of vertex for parabola #y = x^2 - 4x - 12#?

##### 1 Answer

Apr 11, 2015

**Part 1: x-intercepts**

The x-intercepts occur at the points on the function where

So, we need to solve

The left side factors fairly easily into:

So solution occur when

and

So the x-intercepts are at

**Part 2: vertex of the parabola**

The vertex of a simple quadratic parabola occurs when the derivative of the quadratic is equal to

The derivative of the given quadratic is

By observation, this is equal to

When

Therefore the vertex of this parabola is at