# How do you find x intercepts of parabola in vertex form y=4(x-3)^2-1?

$f \left(x\right) = 4 \left({x}^{2} - 6 x + 9\right) - 1 = 4 {x}^{2} - 24 x + 35 = 0.$
$f \left(x\right) = 4 {x}^{2} - 24 x = 35 = 0 \left(1\right)$. There are many methods. I use the transforming Method (Google, Yahoo Search).