How do you foil $(2 x - 5) (x + 3)$ $(2x-5)(x+3)$ ?

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Answer 1 · 2018-05-06T19:38:49

$2 x^{2} + x - 15$ $2x^2 + x -15$

F.O.I.L.

First, Outer, Inner Last

Multiply your first terms:

(2x - 5)(x + 3)

$2 x \cdot x = 2 x^{2}$ $2x * x = 2x^2$

Multiply your outer terms:

(2x - 5)(x + 3)

$2 x \cdot 3 = 6 x$ $2x * 3 = 6x$

Multiply your inner terms:

(2x - 5)(x + 3)

$- 5 \cdot x = - 5 x$ $-5 * x = -5x$

Multiply your last terms:

(2x -5)(x + 3)

$- 5 \cdot 3 = - 15$ $-5 * 3 = -15$

Add all your terms together.

$2 x^{2} + 6 x - 5 x - 15$ $2x^2 + 6x - 5x - 15$

Simplify.

$2 x^{2} + x - 15$ $2x^2 + x -15$

How do you foil (2x-5)(x+3)(2x−5)(x+3)(2x-5)(x+3)?