How do you FOIL #(4z-u)(3z+2u)#?
The FOIL'ed version of the factored expression is
As you may know, FOIL stands for First Outer Inner Last. Using this Mnemonic, we'll work in order.
Now, let's put them back together in the expression:
Finally we combine like terms to get our finished expression:
The FOIL method:
#(4z−u)(3z+2u)# #(4z*3z) +(4z * 2u) + (-u*3z) + (-u * 2u)# #12z^2 +8zu -3zu - 2u^2# #12z^2 +5zu -2u^2#
Hope this helps!
The inside would be
Finally, you solve the last two...
You're equation should now look like this;
You should get
Your final equation should look like this;