# How do you graph 2x+3y=3 using intercepts?

Jul 16, 2017

#### Explanation:

$x$-intercept is where $y = 0$ i.e. $2 x + 3 \times 0 = 3$ or $2 x = 3$ and $x = 1.5$ i.e. line passes through $\left(1.5 , 0\right)$.

$y$-intercept is where $x = 0$ i.e. $2 \times 0 + 3 y = 3$ or $3 y = 3$ and $y = 1$ i.e. line passes through $\left(0 , 1\right)$.

Now join $\left(1.5 , 0\right)$ and $\left(0 , 1\right)$ to get the line.

graph{(2x+3y-3)((x-1.5)^2+y^2-0.003)(x^2+(y-1)^2-0.003)=0 [-1.917, 3.082, -0.77, 1.73]}

Tip - If intercept on $x$-axis is$a$ and intercept on $y$-axis is $b$, equation of line is $\frac{x}{a} + \frac{y}{b} = 1$.