# How do you graph 2x – 4y > 8 and y <3x + 1?

Nov 5, 2017

#### Explanation:

to get the intersections with the coordinate axes
for with the x axis y=0

$2 x - 4 y = 8$
when y=0
$2 x = 8$
$x = 4$
then is the point (4,0)

now with the y axis, x=0
when x=0

$2 x - 4 y = 8$
$- 4 y = 8$
$y = - 2$
then is the point (0;-2)

then both points are located and the straight line is obtained
by being an inequality and having the greater sign, a line segment and shaded down is graphed

now $y < 3 x + 1$

same for y=0

$0 < 3 x + 1$
$- \frac{1}{3} = x$

for x=0

$y < 1$
$y = 1$

it can also write as $3 x + 1 > y$ by being an inequality and having the greater sign, a line segment and shaded down is graphed