# How do you graph #36x^2-4y^2=144# and identify the foci and asympototes?

##### 1 Answer

Nov 10, 2016

The foci are F

The equations of the asymptotes are

#### Explanation:

The equation represents a hyperbola.

The general equation is

The center is

The vertices are

The vertices are

The slope of the asymptotes are

The equations of the asymptotes are

To determine the foci, we need

the foci are

the foci are F

graph{(x^2/4-y^2/36-1)(y+3x)(y-3x)=0 [-18.02, 18.03, -9, 9.02]}