How do you graph #3sec(3x)#?
1 Answer
Jul 25, 2018
See graph and details.
Explanation:
Period = period of
Asynptotes
See Graph.
graph{(y cos (3x ) - 3)(y^2-9) = 0[-20 20 -10 10]}
Graph for one period
graph{(y cos (3x ) - 3)(y^2-9)(x-1.04+0.001y) (x+1.04+0.001y)(x-0.52+0.001y) (x+0.52+0.001y)= 0[-3 3 -6 6 ]}