How do you graph #3x<=1# on the coordinate plane?

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Answer 1 · 2017-11-01T01:23:58

See a solution process below:

Divide each side of the inequality by #color(red)(3)# to solve for #x# while keeping the inequality balanced:

#(3x)/color(red)(2) <= 1/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) <= 1/3#

#x >= 1/3#

To graph this we will draw a vertical line at #1/3# on the horizontal axis.

The line will be a solid line because the inequality operator contains an "or equal to" clause.

We will shade to the left side of the line because the inequality operator also contains a "less than" clause:

graph{x <= 1/3 [-2, 2, -1, 1]}