How do you graph #-5x+y=1#?

1 Answer
Apr 1, 2017

Start by finding the #x#- and #y#-intercepts. Then draw the line connecting those points to get the graph for #-5x+y=1#.
(See explanation for graph)

Explanation:

It might help to rewrite the equation in #y=mx+b# form (general form) to give: #y=5x+1#.

When graphing equations, it's easiest to start with the points of intercepts.

The #x#-intercept is the point where #y=0#
#0=5x+1#
#x=-1/5#
So the point is: #(-1/5,0)#

The #y#-intercept is the point where #x=0#
#y=5(0)+1#
#y=1#
So the point is: #(0,1)#

Plotting these two points on a graph and drawing the line through them (with a slope of 5), gives:
graph{5x+1 [-2.448, 2.552, -0.58, 1.92]}