# How do you graph and label the vertex and axis of symmetry of #y=(x+2)^2-3#?

##### 1 Answer

Using the information given to you and a bit of expanding.

#### Explanation:

Lets start with the known information.

From this we can identify the the vertex of the graph which as we know would be

We can also work out the roots by solving for x with the given completed square. There set y = to 0 and solve,

Now we have our roots of the graph.

Now finally its time for the y-intercept, this can easily be obtained by expanding out the given completed square.

This

Now all we need to do is plot the key points and sketch the graph. graph{y=(x+2)^2-3 [-10, 10, -5, 5]}