How do you graph #f(x)=4(2^x)+1# and state the domain and range?

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jos Share
Jun 17, 2018

Answer:

Dom(f)= R
Range(f)={y|1<y}

Explanation:

#4(2^x)+1#
#=(2^2)(2^x)+1#
#=2^(x+2)+1#

graph of #f(x)=4(2^x)+1# is
vertical shift=-2
horizontal shift=1

shift graph of #f(x)=2^x# to left 2 units and upward 1 unit.

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