# How do you graph f(x) = 4^x + 2?

Aug 15, 2015

Plot points according to the formula, making sure to use both positive and negative values for $x$. Most negative values for $x$ will not result in whole numbers for the $y$ values. The graph is a vertical asymptote.

#### Explanation:

Substitute $y$ for $f \left(x\right)$.

$y = {4}^{x} + 2$

Determine several points using the equation, making sure to include negative as well as positive values for $x$.

Points
$x = - 3 , y = 2.0156$
$x = - 2 , y = 2.0625$
$x = - 1 , y = 2.25$
$x = 0 , y = 3$
$x = 1 , y = 6$
$x = 2 , y = 18$
$x = 3 , y = 66$

Plot your points. The graph will be an asymptote.

graph{y=4^x+2 [-14.24, 14.23, -7.11, 7.12]}