How do you graph #f(x) = 4^x + 2#?

1 Answer
Aug 15, 2015

Answer:

Plot points according to the formula, making sure to use both positive and negative values for #x#. Most negative values for #x# will not result in whole numbers for the #y# values. The graph is a vertical asymptote.

Explanation:

Substitute #y# for #f(x)#.

#y=4^x+2#

Determine several points using the equation, making sure to include negative as well as positive values for #x#.

Points
#x=-3, y=2.0156#
#x=-2, y=2.0625#
#x=-1, y=2.25#
#x=0, y=3#
#x=1, y=6#
#x=2, y=18#
#x=3, y=66#

Plot your points. The graph will be an asymptote.

graph{y=4^x+2 [-14.24, 14.23, -7.11, 7.12]}