Question

How do you graph `F(x)=log_3(x-2)`?

Answer 1

`(3,0),(11,2),(5,1)`

Explanation:

`1.` Find asymptotes.

`x-2=0`
`x=2`
So, the vertical asymptote is `2`

`2.` Find the points

• at `x=3`
  `log_3(3-2)=log_3(1)=0->(3,0)`

• at `x=5`
  `log_3(5-2)=log_3(3)=1->(5,1)`

• at `x=11`
  `log_3(11-2)=log_3(9)=2->(11,2)`

`3.`Now, plot and graph !