# How do you graph h(x)= -5/3 absx + 6?

Aug 10, 2018

See explanation and $\angle$-shaped graph.

#### Explanation:

Here,

$\left\mid x \right\mid = \frac{3}{5} \left(6 - h\right) \ge 0 \Rightarrow h \le 6$. Use, y for h.

Socratic inverted V graph is immediate.
graph{(abs (x) -0.6(6-y))(y-6+0x)=0[-16 16 -8 8]}

The vertex is ( 0, 6 ). You can see the graph, with $h \le 6$.

If you change $\left\mid x \right\mid \to x$, the graph would be as shown below.
graph{(x - 0.6(6-y))(x+0.6(6-y))=0[-10 20 0 15]}

For this, the equation is (x-0.6(6-h)(x+0.6(6-h)) = 0,

for the whole patr of straight lines..