# How do you graph h(x)=ln(x+6)?

Jul 28, 2018

below

#### Explanation:

The graph $h \left(x\right) = I n \left(x + 6\right)$ is basically the graph $y = I n x$ but shifted to the left by $6$ units.

SO, for its intercepts
When $y = 0$, $x = - 5$
When $x = 0$, $y = I n 6$

Plot the intercepts $\left(- 5 , 0\right)$ and $\left(0 , I n 6\right)$ and remember to draw an asymptote at $x = - 6$ as you cannot log $0$ and negative numbers

graph{log(x+6) [-10, 10, -5, 5]}