How do you graph #sqrt(ln x) #?
1 Answer
Feb 16, 2016
See the graph drawn below
Explanation:
-
#ln0# is undefined. It's not a real number, because you can never get zero by raising anything to the power of anything else. -
Also, function
#lnx# is negative for all values of#x<1# , as square root of given function is real only for#x>=0# . -
Hence point
#(1,0)# lies on the graph and the graph does not exist for all values of#x<1# -
Graph increases as square root of a logarithmic for all positive values of
#x#
graph{y=(ln x)^(1/2) [-0.35, 9.104, -0.55, 4.18]}
