How do you graph #tan(x/2) + 1#?

1 Answer
Mar 29, 2018

Answer:

graph{tan(x/2)+1 [-10, 10, -5, 5]}

Explanation:

You first have to know what the graph of #tan(x)# looks like

graph{tan(x) [-10, 10, -5, 5]}

It has vertical assymptotes at #pi# intervals so the period is #pi# and when x=0 y=0

So if you have #tan(x)+1# it shifts all the y values up by one

#tan(x/2)# is a vertical shift and it doubles the period to #2pi#

graph{tan(x/2)+1 [-10, 10, -5, 5]}