How do you graph the equation by plotting points #y = 1/(1 + x^2)#?

1 Answer
Feb 27, 2016

Answer:

You make a list of #x#-values and the corresponding #y#-values.

Explanation:

The points will be all #(x,y)# combinations you calculated.
Notice that #x# is only in #x^2# form, so the negative values of #x# will give the same result as the positive. In other words, the graph is symmetrical with #x=0# as axis of symmetry.
Maximum will be at #(0,1)# and #y=0# is the horizontal asymptote
graph{1/(1+x^2) [-4.382, 4.386, -2.19, 2.192]}