How do you graph the equation by plotting points #y = (2/3)(x) - 5#?

1 Answer
Jan 11, 2018

Answer:

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = ((2/3) * 0) - 5#

#y = 0 - 5#

#y = -5# or #(0, -5)#

Second Point: For #x = 3#

#y = ((2/3) * 3) - 5#

#y = 2 - 5#

#y = -3# or #(3, -3)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+5)^2-0.075)((x-3)^2+(y+3)^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - (2/3)x + 5)(x^2+(y+5)^2-0.075)((x-3)^2+(y+3)^2-0.075)=0 [-20, 20, -10, 10]}