# How do you graph the inequality  y + 2<= -2/3(x - 6).?

Aug 30, 2016

You can rewrite the inequality in slope-intercept form:

#### Explanation:

First work away the parentheses:
$y + 2 \le - \frac{2}{3} x - \frac{2}{3} \left(- 6\right) \to$
$y + 2 \le - \frac{2}{3} x + 4 \to y \le - \frac{2}{3} x + 2$

If you graph the line of $y = - \frac{2}{3} x + 2$, the line itself and everything under it fits the inequality.

The $y$-intercept will be $x = 0 \to \left(0 , 2\right)$,
the $x$-intercept will be $y = 0 \to \left(3 , 0\right)$
graph{-2/3x+2 [-10, 10, -5, 5]}