Question

How do you graph the inequality `y + 2<= -2/3(x - 6).`?

Answer 1

You can rewrite the inequality in slope-intercept form:

Explanation:

First work away the parentheses:
`y+2<=-2/3x-2/3(-6)->`
`y+2<=-2/3x+4->y<=-2/3x+2`

If you graph the line of `y=-2/3x+2`, the line itself and everything under it fits the inequality.

The `y`-intercept will be `x=0->(0,2)`,
the `x`-intercept will be `y=0->(3,0)`
graph{-2/3x+2 [-10, 10, -5, 5]}