How do you graph the inequality #y<=-3abs(x-2)+4#?

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Answer 1 · 2016-12-02T04:21:20

Upon the collar-graph and the neck within, #y<=-3|x-2|+4#. The vertex of the collar is (2, 4)

#y<=-3|x-2|+4# is the combined equation for the pair

#y<=-3(x-2)+4, x>=2# and

#y<=-3(-(x-2))+4, x<=2#

representing two straight lines meeting at ( 2, 4 ).

See the graph.

Upon the collar-graph and the neck within, #y<=-3|x-2|+4#.

graph{y+3|x-2|-4=0 [-40, 40, -20, 20]}