# How do you graph the inequality y<sqrt(x+3)+5?

Nov 16, 2016

#### Explanation:

The reason for the graph looking like this, is because $y = \sqrt{x}$ is a parabola on its side, but in order for this to be a function, the values for the range can only be positive. All you do from here, are the horizontal and vertical shifts ($y = \sqrt{x + h} + k$). ($- h , k$) are the coordinates of the new vertex. the $h$ is the horizontal shift ($- 3$) and the $k$ is the vertical shift ($5$)

Nov 16, 2016