# How do you graph the inequality y<=-x^2+5x+6?

Oct 12, 2017

it's a parabola

#### Explanation:

you can find the x-intercepts using the quadratic equation
$- b \pm \frac{\sqrt{{\left(b\right)}^{2} - 4 \cdot a \cdot c}}{2 \cdot a}$
then find the vertex by using (-b)/(2*a and $f \left(\frac{- b}{2 \cdot a}\right)$
Then to solve for the inequality, use the coordinates (0,0) for the x and y points, with your equation
y ≤ −x^2+5x+6
you get 0 ≤ 6
since this is true, the area that contains the coordinate (0,0) is the correct area