How do you graph the line through (2,-9) perpendicular to x + 2y = 8?

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Answer 1 · 2017-06-27T13:34:13

See below.

We must first find the slope of the given line.

#x+2y=8#

#2y=8-x#

#y=4-1/2x#

So, the perpendicular line's slope is the opposite inverse of the given line, or #2#.

Since we are given that it passes through a point, we may use point-slope to write out the line.

Point-Slope: #y-y_0=m(x-x_0)#

Plugging in,

#y-(-9)=2(x-2)#

#y=2x-4-9#

#y=2x-13#

We can now graph this.

graph{2x-13 [-12.58, 27.42, -8.44, 11.56]}