How do you graph the parabola #f(x)=-3x^2+x-5# using vertex, intercepts and additional points?
As a first step, if we just look at the equation we can see that the
I'd use the quadratic formula to solve this:
Help me out, colleagues: this yields imaginary roots. Not sure what the issue is. I'll work on the rest of the question but leave it with this query.
To find the vertex, we will use some calculus. The first derivative of the function,
This will be equal to zero at the vertex, because the slope goes to zero momentarily as it changes from positive to negative.
To find the other coordinate of the vertex we substitute this into the expression for
Knowing the intercepts and the vertex, and that it is a narrow, upside down parabola, should be enough to draw a graph, but remember that you can also easily calculate a few additional points on the parabola. Substituting in points 1 unit either side of the