# How do you graph the system of linear inequalities #x-y>7# and #2x+y<8#?

##### 1 Answer

See below:

#### Explanation:

Let's first graph the boundary lines for each graph, then figure out what needs to be shaded. To graph the boundary lines, I'll change the form of the equations to slope-intercept:

graph{x-7[-40,40,-20,20]}

To shade, does the origin fall within the solution?

And so we shade the other side:

graph{y -x+7< 0[-40,40,-20,20]}

graph{2x+8[-40,40,-20,20]}

Is the origin part of this solution?

So we shade that side:

graph{y-2x-8<0[-40,40,-20,20]}

To put the graphs together, you'll shade to the right of the line that is rightmost (so "above" the point of intersection, it's

The point of intersection sits at: