Question

How do you graph to solve the equation on the interval `[-2pi,2pi]` for `tanx=1`?

Answer 1

(`-(7pi)/4,-(3pi)/4,pi/4,(5pi)/4`)

Explanation:

Solving for x:
`tanx=1`
`x=arctan1`
When the tangent of an angle is 1, we know that the lengths of the non hypotenuse sides are equal and have the same sign. So:
We know that the values of angles x and y are `pi/4`, and we need to add those values to known values on the interval. The solutions will be (`-2pi+pi/4`, `-pi+pi/4`, `pi/4`, `pi+pi/4`), which simplifies to:

(`-(7pi)/4,-(3pi)/4,pi/4,(5pi)/4`)