How do you graph using slope and intercept of 2x-3y=72x3y=7?

1 Answer
Apr 2, 2018

See below

Explanation:

Remember that slope intercept form is y = mx + by=mx+b where m is slope and b is the y intercept

So we must put the function in slope intercept form as such:

2x-3y=72x3y=7

-3y = -2x + 73y=2x+7

y = 2/3x - 7/3y=23x73

To graph the equation, we place a point on the graph where x = 0 (y intercept) at the value y =-7/3y=73, then we draw a line with a slope of 2/323 that runs through that line.
graph{y = (2/3x) - (7/3) [-3.85, 6.15, -3.68, 1.32]}