# How do you graph using slope and intercept of #6x - 12y = 24#?

##### 2 Answers

Re-arrange the equation to get the base form of y=mx+b (slope-intercept form), build a table of points, then graph those points.

graph{0.5x-2 [-10, 10, -5, 5]}

#### Explanation:

The slope-intercept line equation is

To get there, we'll need to rearrange the starting equation some. First off is to move the 6x to the right-hand side of the equation. We'll do that by subtracting 6x from both sides:

Next, we'll divide both sides by y's coefficient, -12:

Now we have our slope intercept form of the equation,

Next, let's build a table of points to plot. Since it's a straight line, we only need 2 points that we can line up with a ruler and draw a straight line through.

We already know one point, which is the y-intercept (0,-2). Let's pick another point, at

So our second point is (10,3). Now we can draw a straight line that passes through both of those points:

graph{0.5x-2 [-10, 10, -5, 5]}

#### Explanation:

First you have to get the y by itself so you subtract 6x from both sides

Then, you want to get one y so you divide both sides by -12

You then graph it so that the y-intercept is at -2, because at the y-intercept, x is always 0. And then you go up 1, over 2 every point after that.