# How do you graph (x^2 / 4) - (y^2 / 9) =1?

You will move right and left 2 units from center to find the vertices. This comes from $\sqrt{4}$ that is the denominator of the ${x}^{2}$ term.
Then, go up and down 3 units ($\sqrt{9}$) to find corners of a "box" that will create asymptotes for your shape. The slopes of the asymptotes will be $\pm \frac{3}{2}$ for these reasons.