Question

How do you graph `(x+5)^2+(y-2)^2=9`?

Answer 1

This is a circle with centre `(-5, 2)` and radius `3`

Explanation:

Given:

`(x+5)^2+(y-2)^2=9`

This can be rewritten slightly as:

`(x-(-5))^2+(y-2)^2 = 3^2`

which is in the standard form:

`(x-h)^2+(y-k)^2=r^2`

which is the equation of a circle with centre `(h, k) = (-5, 2)` and radius `r=3`.

graph{((x+5)^2+(y-2)^2-9)((x+5)^2+(y-2)^2-0.02) = 0 [-15.75, 4.25, -3.12, 6.88]}